OEE Improvement ROI Calculator

This OEE improvement ROI (return on investment) calculator works out, in five steps, whether an investment that raises the OEE of a machine or line pays for itself, and when. Planned Production Time counts the hours a year in which the machine is planned to produce, Losses Now prices the hours lost at the current OEE, Improvement values the hours a higher OEE would recover, Investment takes the one-off and monthly costs, and Payback and Return sets the value against the costs month by month: the payback month, the net gain, the return and the net present value. The investment can be machine monitoring, shorter changeovers or better maintenance: anything whose effect is a higher OEE.

The current OEE comes from the OEE calculator, and the default value of a recovered hour, the cost of one hour, from the machine hour rate calculator.

The results can be downloaded as a PNG or copied as text at the end of the page.

Calculator by Jacek Garbuliński, Blixild. Updated 19 October 2026.

Worked Example

The calculator opens with a worked example using illustrative values, not data from a plant: the machine of the OEE calculator’s worked example, planned for 10 shifts a week of 480 min, each with 30 min of planned stops, 48 weeks a year: 3,600 planned production hours. Its OEE is 64%, and an hour of it costs $60 whether it runs or not, the result of the machine hour rate calculator’s worked example. At 64%, 1,296 hours a year are lost, at a cost of $77,760.

The investment is a cloud machine monitoring subscription with the sensor included, at one supplier’s published starting price per machine, before VAT, converted from euros and rounded (October 2026): $150 once and $140 a month. It is assumed to raise the OEE to 70%, reached over 6 months; 70% is the median OEE in a study of automatic OEE measurement at 23 companies (Hedman, Subramaniyan and Almström, 2016, 4.1). The gain comes from acting on the losses the monitoring shows; the staff time this takes is not in the $140 and would be added to it. The 6 percentage points recover 216 hours a year, worth $12,960.

Over 3 years the investment pays back in month 2 and leaves a net gain of $30,990 on $5,190 spent, a return of 597% over the 3 years; its net present value at 7% a year is $27,726. The result rests on the assumed gain: at 3 points instead of 6, the net gain over 3 years is $12,900, and below about 0.9 points the investment does not pay back within 3 years. Doubling the price of monitoring lowers the net gain to $25,800.

Planned Production Time

This step counts the hours a year in which the machine is planned to produce.

An OEE gain recovers a share of the planned production time: the shift less its planned stops, such as breaks and planned maintenance, as in the OEE calculator. The more hours are planned, the more each point of OEE is worth: one point of 3,600 hours is 36 hours a year.

Planned production time

T_{pp}

450 min(7h30min)

Planned production hours a year

H

3,600 h

H = \frac{T_s - T_{pl}}{60}\, n_s\, n_w

where $H$ is the number of planned production hours a year; $T_s$ is the shift length and $T_{pl}$ the planned stops, in minutes; 60 is the number of minutes in an hour; $n_s$ is the number of shifts per week and $n_w$ the number of weeks per year.

Planned production time 480 − 30 = 450 min = 7.5 h a shift; planned production hours 7.5 h × 10 × 48 = 3,600 h a year.

Equations

T_{pp} = T_s - T_{pl}

H = \frac{T_{pp}}{60}\, n_s\, n_w

$T_{pp}$ is the planned production time of one shift: the shift length $T_s$ less the planned stops $T_{pl}$ , in minutes. $H$ is the number of planned production hours in a year: $T_{pp}$ divided by 60, times $n_s$ shifts a week and $n_w$ weeks a year.

Planned stops are left out because OEE leaves them out: “Scheduled downtime should therefore not be used in OEE calculation” (Muchiri and Pintelon, 2008).

Assumptions

The year repeats the shift entered: all the shifts are assumed to be alike.

Losses Now

This step prices the planned production time lost at the current OEE.

OEE is the share of the planned production time that is fully productive: the machine running at its ideal cycle and making good parts. The rest, 100% less the OEE, is lost to downtime, speed losses and rejects. This step values the lost hours at the value of a recovered hour, as the OEE calculator’s Cost of Losses step does with the cost of one hour, to show what is at stake before any improvement.

Uses the planned production hours from Planned Production Time.

Lost hours a year

H_L

1,296 h

Cost of the losses a year

K_y

$77,760

H_L = H\,(1 - \mathrm{OEE}_0) \qquad K_y = v\,H_L

where $H_L$ is the number of planned production hours lost a year; $H$ is the number of planned production hours a year, from Planned Production Time; $\mathrm{OEE}_0$ is the current OEE, written as a fraction; $K_y$ is the cost of the losses a year, at $v$ , the value of a recovered hour.

Lost hours 3,600 h × (100% − 64%) = 1,296 h a year; cost of the losses 1,296 h × $60 = $77,760 a year.

Equations

H_L = H\,(1 - \mathrm{OEE}_0)

K_y = v\,H_L

$H_L$ is the number of planned production hours lost in a year at the current OEE, $\mathrm{OEE}_0$ , written as a fraction. $K_y$ is their cost: the value of a recovered hour $v$ times $H_L$ . At the cost of one hour, $K_y$ equals the OEE calculator’s cost of all losses in a year.

Assumptions

Pricing the losses is the calculators’ own method: Muchiri and Pintelon (2008) note that cost is not measured in OEE.
One value is used for every lost hour.
At the cost of one hour, the losses are priced as capacity paid for and not used, not as cash. They become cash only when the recovered hours avoid a cost, such as overtime or an extra shift (then the value to enter is the cost avoided per hour), or when the extra output is sold (then it is the contribution margin).

Improvement

This step values the hours a higher OEE would recover.

Each point of OEE gained recovers 1% of the planned production time. The target is the OEE the investment is expected to reach; the calculator does not estimate it. Measuring OEE does not raise it by itself: in a study of automatic OEE measurement at 23 companies, almost half of the recorded losses could not be classified, and, for those who decide on improvements, much of the improvement potential stays hidden when the causes of losses are not communicated (Hedman, Subramaniyan and Almström, 2016, abstract and 5). The gain comes from acting on the causes, so it grows over the first months: the ramp.

Uses the planned production hours from Planned Production Time, and the current OEE and the value of a recovered hour from Losses Now.

OEE gained

\Delta \mathrm{OEE}

6 points

Hours recovered a year

\Delta H

216 h

Value of the recovered hours a year

B

$12,960

\Delta H = H\,(\mathrm{OEE}_1 - \mathrm{OEE}_0) \qquad B = v\,\Delta H

where $\Delta H$ is the number of planned production hours recovered a year; $H$ is the number of planned production hours a year, from Planned Production Time; $\mathrm{OEE}_1$ is the target OEE and $\mathrm{OEE}_0$ the current one, written as fractions; $B$ is the value of the recovered hours a year at the full gain, at $v$ , the value of a recovered hour.

OEE gained 70% − 64% = 6 points; hours recovered 3,600 h × 6% = 216 h a year; their value 216 h × $60 = $12,960 a year, reached after a 6-month ramp.

Equations

\Delta H = H\,(\mathrm{OEE}_1 - \mathrm{OEE}_0)

B = v\,\Delta H

b_k = \frac{B}{12}\,\min\!\left(\frac{k}{R},\, 1\right)

$\Delta H$ is the number of planned production hours recovered in a year when the OEE rises from $\mathrm{OEE}_0$ to the target $\mathrm{OEE}_1$ , both written as fractions. $B$ is their value in a year at the full gain. $b_k$ is the value in month $k$ : a twelfth of $B$ , times $k/R$ during the ramp of $R$ months; with no ramp ( $R = 0$ ) it is a twelfth of $B$ from the first month.

Assumptions

One OEE is used: the gain can come from availability, performance or quality. As OEE is their product, “OEE = A * P * Q” (Muchiri and Pintelon, 2008), run time recovered from downtime raises OEE only by that time times the current performance and quality.
The gain, once reached, lasts to the end of the horizon.
The gain grows in equal monthly steps during the ramp. That is this calculator’s convention.

Investment

This step takes the costs of the investment: what is paid once and what is paid every month.

Where machine monitoring prices are published, they are mostly a monthly subscription per machine, with a small one-off fee or none; other improvements, such as changeover equipment, are paid mostly once. Enter both parts for the machine or line above. Costs shared with other machines, such as a plant-wide software licence, are entered as this machine’s share.

Running cost a year

C_y

$1,680

C_y = 12\,C_m

where $C_y$ is the running cost a year; 12 is the number of months in a year; $C_m$ is the running cost a month.

Running cost $140 × 12 = $1,680 a year; one-off cost $150.

Equations

C_y = 12\,C_m

$C_y$ is the running cost in a year: twelve times the running cost a month $C_m$ . The one-off cost $C_0$ is paid at the start of the first month.

Assumptions

The costs stay the same over the horizon; prices do not rise.
Taxes and the financing of the investment are left out; the discount rate in the next step accounts for the cost of money.

Payback and Return

This step sets the value of the recovered hours against the costs, month by month, over the horizon.

Each month the recovered hours bring their value, less the running cost; the one-off cost is paid at the start. The payback is the first month in which the cumulative net gain is no longer negative. Payback does not account for the time value of money (OpenStax, 2019, 11.2), so the net present value is shown too: each month’s net gain discounted at the discount rate (11.4). The return over the horizon is the net gain divided by everything spent. At the cost of one hour, the net gain is capacity recovered, not cash; it becomes cash only as far as the recovered hours avoid costs or make output that is sold.

Uses the value of the recovered hours and the ramp from Improvement, and the costs from Investment.

Payback

k^{*}

Month 2

Net gain over the horizon

S_{12T}

$30,990

Spent over the horizon$5,190

Return over the horizon

\rho

597%

Net present value$27,726

S_k = -C_0 + \sum_{j=1}^{k} (b_j - C_m)

\rho = \frac{S_{12T}}{C_0 + 12\,T\,C_m}

\mathrm{NPV} = -C_0 + \sum_{k=1}^{12T} \frac{b_k - C_m}{(1 + r)^{k/12}}

where $S_k$ is the cumulative net gain after month $k$ ; $C_0$ is the one-off cost and $C_m$ the running cost a month; $b_j$ and $b_k$ are the value of the recovered hours in months $j$ and $k$ , growing during the ramp; $\rho$ is the return over the horizon of $T$ years, 12 months a year, $S_{12T}$ the net gain at its end; $\mathrm{NPV}$ is the net present value at the yearly discount rate $r$ , written as a fraction.

Cumulative net gain −$110 after month 1 and $110 after month 2: payback in month 2. Over 36 months: value of the recovered hours $36,180 (36 × $1,080, less the $2,700 not earned during the ramp); spent $150 + 36 × $140 = $5,190; net gain $36,180 − $5,190 = $30,990; return over 3 years $30,990 ÷ $5,190 = 597%; net present value at 7% $27,726.

Whether the OEE gain assumed here is reached can be measured from camera images, before and after the investment: machine monitoring.

Equations

S_k = -C_0 + \sum_{j=1}^{k} (b_j - C_m)

k^{*} = \min\{\, k \ge 1 : S_k \ge 0 \,\}

\rho = \frac{S_{12T}}{C_0 + 12\,T\,C_m}

\mathrm{NPV} = -C_0 + \sum_{k=1}^{12T} \frac{b_k - C_m}{(1 + r)^{k/12}}

$S_k$ is the cumulative net gain after month $k$ : minus the one-off cost $C_0$ , plus each month’s value $b_j$ less the running cost $C_m$ . The payback $k^{*}$ is the first month in which $S_k$ is no longer negative. $\rho$ is the return: the net gain at the end of the horizon of $T$ years, $S_{12T}$ , divided by everything spent over it. $\mathrm{NPV}$ is the net present value: each month’s net gain discounted at the yearly rate $r$ , written as a fraction, less the one-off cost.

The payback method computes “the length of time it takes a company to recover their initial investment”; it counts cost savings as cash inflows and works with uneven cash flows, such as the ramp’s (OpenStax, 2019, 11.2). Net present value “discounts future cash flows to their present value at the expected rate of return and compares that to the initial investment” (11.4).

Assumptions

Each month’s gain and running cost come at the end of the month and are discounted by $(1 + r)^{k/12}$ , so the rate entered is a yearly rate. That is this calculator’s convention.
The return divides by everything spent, not by the one-off cost alone: where monitoring prices are published, they are mostly subscriptions, and the one-off cost can be small or nil. It is this calculator’s own measure; OpenStax’s accounting rate of return (2019, 11.2) relates net income, not cash, to the initial investment.
Nothing is counted after the horizon, and no value is left at its end.

Cite as: Jacek Garbuliński, OEE Improvement ROI Calculator, Blixild, 2026, https://blixild.com/oee-improvement-roi-calculator.html

Questions and Answers

When should I use this calculator?

Before an investment whose purpose is a higher OEE: machine monitoring, shorter changeovers, a maintenance programme. It shows whether the gain the investment needs would pay for it, and when. It also works the other way round: change the target OEE until the payback falls where the business needs it, and the result is the gain the investment has to deliver. With estimates instead of measured figures, the result is indicative only.

What OEE gain should I enter?

Estimate it from the losses the investment addresses: if changeovers take 40 min of a 450-min shift and the investment halves them, it adds 20 min of run time; at the performance and quality of the OEE calculator’s example, 74% and 96%, that is 14 min of fully productive time, 3.2 points of OEE. At 23 companies measuring OEE automatically, Hedman, Subramaniyan and Almström (2016, 4.1) found a median of 70% and an average of 65%, closer to availability, as most machines recorded performance and quality at 100%: a rough guide to where a machine stands, not to how much it will gain. Gains quoted in suppliers’ case studies are the suppliers’ own reports, not independent measurements.

Why is a recovered hour valued at the cost of one hour?

Because the plant pays for every planned hour whether the machine runs or not, and the OEE calculator prices its losses the same way. At that value the result shows the capacity recovered, not cash. It turns into cash only when the recovered hours avoid a cost, such as overtime or an extra shift, or when the extra output is sold. Then enter the cost avoided per hour, or the contribution margin of the good parts made in an hour at the ideal cycle: their selling price less their variable cost (OpenStax, 2019, 3.1).

Why is the return divided by everything spent?

Because, where machine monitoring prices are published, they are mostly subscriptions. The one-off cost can be small or nil, and a return on the one-off cost alone would run to thousands of per cent, or could not be computed. Dividing the net gain by everything spent over the horizon, the one-off and the running costs, gives the return on what the investment actually costs. It is this calculator’s own measure: OpenStax’s accounting rate of return (2019, 11.2) relates net income to the initial investment.

Where do the numbers come from?

The current OEE comes from the OEE calculator or the plant’s records, and the value of an hour from the machine hour rate calculator or, for output that can be sold, from the selling prices and variable costs. The costs come from the supplier’s quote, the discount rate from the firm’s finance department, and the shift pattern from the shift plan. The target OEE is an estimate; the current OEE, and later the gain, can be measured from camera images (machine monitoring).

Sources

Franklin, M., Graybeal, P., Cooper, D. (2019). Principles of Accounting, Volume 2: Managerial Accounting. Houston, TX: OpenStax, Rice University. Chapter 11, Capital Budgeting Decisions (11.2, 11.4); chapter 3, Cost-Volume-Profit Analysis (3.1). https://openstax.org/books/principles-managerial-accounting/pages/11-2-evaluate-the-payback-and-accounting-rate-of-return-in-capital-investment-decisions https://openstax.org/books/principles-managerial-accounting/pages/11-4-use-discounted-cash-flow-models-to-make-capital-investment-decisions https://openstax.org/books/principles-managerial-accounting/pages/3-1-explain-contribution-margin-and-calculate-contribution-margin-per-unit-contribution-margin-ratio-and-total-contribution-margin

Muchiri, P., Pintelon, L. (2008). Performance measurement using overall equipment effectiveness (OEE): literature review and practical application discussion. International Journal of Production Research, 46(13), 3517-3535. https://doi.org/10.1080/00207540601142645

Hedman, R., Subramaniyan, M., Almström, P. (2016). Analysis of critical factors for automatic measurement of OEE. Procedia CIRP, 57, 128-133. https://doi.org/10.1016/j.procir.2016.11.023

Send an enquiry

To measure a machine’s OEE from camera images, before and after an improvement, send an enquiry.

Describe your requirements briefly. We respond within one business day.

contact@blixild.com